Question

A classroom is 11 m long, 8 m wide and 5 m high. Find the sum of the areas of its floor and the four walls (including doors, windows etc.)

Answer 1

Given details are:
$\text{Dimensions of class room}=11m\times 8m\times 5m$
Where, Length = 11m, Breadth = 8m, Height = 5m
We know,
Area of floor = length $\times$ breadth
$=11\times 8$ $=88m^2$
Area of four walls (including doors & windows) $=2(lh+bh)c{m}^2$
$=2(11\times 5+8\times 5)$
$=2(55+40)$
$=2\left(95\right)$
$=190m^2$
Sum of areas of floor and four walls = area of floor + area of four walls
$=88+190$
$=278m^2$