Question

A cloassroom is $11m$ long, $8m$ wide and $5m$ high. Find the sum of the areas of its floor and the four walls (including doors, windows, etc.)

Answer 1

Given class room dimensions are
length $=11m$, Width$=8m$ and Height$=5m$ .
We have to find the sum of the areas of its floor and the four walls
(i.e., like an open box).
Therefore, the sum of areas of the floor and the four walls
$=$(length$\times$width)$+2\times$(width $\times$ height$+$length$\times$height)
$=(11\times 8)+2\times (8\times 5+11\times 5)$
$=88+2\times (40+55)$
$=88+(2\times 95)$
$=88+190$
$=278m^2$ is the required area.