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Standard VIII

Mathematics

Volume of a Cuboid

A classroom i...

Question

A classroom is 11 m long, 8 m wide and 5 m high. Find the sum of the areas of its floor and the four walls (including doors, windows etc.)

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Solution

Given details are:
$Dimensions of class room = 11 m \times 8 m \times 5 m$
Where, Length = 11m, Breadth = 8m, Height = 5m
We know,
Area of floor = length $\times$ breadth
$= 11 \times 8$ $= 88 m^{2}$
Area of four walls (including doors & windows) $= 2 (l h + b h) c m^{2}$
$= 2 (11 \times 5 + 8 \times 5)$
$= 2 (55 + 40)$
$= 2 (95)$
$= 190 m^{2}$
Sum of areas of floor and four walls = area of floor + area of four walls
$= 88 + 190$
$= 278 m^{2}$

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