A closed box made of wood of uniform thickness has length, breadth and height as 12cm,10cm and 8cm, respectively. If the thickness of the wood is 1cm, the inner surface area is
A
456cm2
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B
376cm2
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C
264cm2
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D
696cm2
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Solution
The correct option is A376cm2 Internal dimensions of the box are : Length =(12−2)cm=10cm Breadth =(10−2)cm=8cm Height =(8−2)=6cm ∴ Inner surface area =2×(10×8+8×6+6×10)cm2 =2×(80+48+60)cm2 =2×188cm2 =376cm2