A closed metal box measures 30 cm -20 cm - 10 cm- Thickness of the metal is 1 cm- The volume of the box is

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Volume and Its Measurement

A closed meta...

Question

A closed metal box measures $30 c m \times 20 c m \times 10 c m$ . Thickness of the metal is 1 cm. The volume of the box is

1041

c m^{3}

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6000

c m^{3}

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4536

c m^{3}

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1968

c m^{3}

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Solution

The correct option is D $1968$ $c m^{3}$
Metal required to make box = External volume $V_{1}$ - Internal volume $V_{2}$
$V_{1} - V_{2} = 30 \times 20 \times 10 - 28 \times 18 \times 8$
$= 6000 - 4032 = 1968 c m^{3}$
(Since thickness is 1 cm each side)

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A closed metal box measures 30cm×20cm×10cm. Thickness of the metal is 1 cm. The volume of the box is

The correct option is D 1968 cm3Metal required to make box = External volume V1 - Internal volume V2V1−V2=30×20×10−28×18×8=6000−4032=1968cm3 (Since thickness is 1 cm each side)

A closed metal box measures $30 c m \times 20 c m \times 10 c m$ . Thickness of the metal is 1 cm. The volume of the box is

The correct option is D $1968$ $c m^{3}$
Metal required to make box = External volume $V_{1}$ - Internal volume $V_{2}$
$V_{1} - V_{2} = 30 \times 20 \times 10 - 28 \times 18 \times 8$
$= 6000 - 4032 = 1968 c m^{3}$
(Since thickness is 1 cm each side)