A closed tea box has 47 cm X 47 cm X 60 cm internal dimensions then the total area of tin foil needed for lining it is

1.57 m

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1.81 m

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1.46 m

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2.10 m

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Solution

The correct option is A 1.57 m
Given That the dimension of closed tea box whose internal dimension is 47 cm ,47 cm and 60 cm
Then the surface area of closed box = $2 (0.47 \times 0.47) + 2 (0.60 \times 0.47) \times 2 (0.47 \times 0.60) = 0.4418 + 0.564 + 0.564 = 1.5698 m$
Then total area of tin foil lining=1.57 m

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A closed tea box has 47 cm X 47 cm X 60 cm internal dimensions then the total area of tin foil needed for lining it is

The correct option is A 1.57 mGiven That the dimension of closed tea box whose internal dimension is 47 cm ,47 cm and 60 cmThen the surface area of closed box =2(0.47×0.47)+2(0.60×0.47)×2(0.47×0.60)=0.4418+0.564+0.564=1.5698mThen total area of tin foil lining=1.57 m