A closed vessel with rigid walls contain 1 mol of 92238 U and 1 mol of air at 298 K- Considering complete decay of 92238 U to 206-82 P b- the ratio of the final pressure to the initial pressure of the system at 298 K is

Initial moles of gases = 1 nbsp; nbsp; nbsp; Initial,1 moles^238_92U→ ^206_82Pb + Final,8 mole8 ^4_2He + 6_ 1e^∘ Total gaseous moles after decompositi ...

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Standard XII

Chemistry

Law of Radioactivity

A closed vess...

Question

A closed vessel with rigid walls contain 1 mol of $_{92}^{238} U$ and 1 mol of air at 298 K. Considering complete decay of $_{92}^{238} U$ to $_{82}^{206} P b$ , the ratio of the final pressure to the initial pressure of the system at 298 K is

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Solution

Initial moles of gases = 1
$_{92}^{238} U Initial,1 moles \to_{82}^{206} P b + 8_{2}^{4} H e + 6_{- 1} e^{\circ} Final,8 mole$

Total gaseous moles after decomposition = 8 + 1 = 9 moles
Ratio of pressures $\frac{P_{f}}{P_{i}} = \frac{n_{f}}{n_{i}} = 9$

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A closed vessel with rigid walls contains 1mole of $_{92}^{238} U$ and 1 mole of air at 298 K. Considering complete decay of $_{92}^{238} U$ to $_{82}^{206} P b$ , the ratio of the final pressure to the initial pressure of the system at 298 K is ___