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Standard VIII

Physics

Expansion of Gases

A closed vess...

Question

A closed vessel with rigid walls contains $1$ mol of $_{92}^{238} U$ and $1$ mol air at $298$ $K$ . Considering complete decay of $_{92}^{238} U$ to $_{82}^{206} P b$ ; the ratio of the final pressure to the initial pressure of the system at $298$ $K$ is:

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Solution

$9$
$_{92}^{238} U {(8 α, 6 β) - ------- \to}_{82}^{206} P b$
On complete decay, $1$ mol of $_{92}^{238} U$ will give $8$ mol of $α$ -particles, i.e., eight mol of ' $H e$ ' gas.
$∴$ Final gas moles in the vessel $= 1 + 8 = 9$
$\frac{P_{F i n a l}}{P_{I n i t i a l}} = \frac{n_{F i n a l}}{n_{I n i t i a l}} = \frac{9}{1}$

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Q. A closed vessel with rigid walls contains 1 mol of

_{92}^{238} U

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A closed vessel with rigid walls contains 1 mol of 23892U and 1 mol air at 298 K. Considering complete decay of 23892U to 20682Pb; the ratio of the final pressure to the initial pressure of the system at 298 K is:

923892U(8α,6β)−−−−−−−−→20682PbOn complete decay, 1 mol of 23892U will give 8 mol of α-particles, i.e., eight mol of 'He' gas.∴ Final gas moles in the vessel =1+8=9PFinalPInitial=nFinalnInitial=91

A closed vessel with rigid walls contains $1$ mol of $_{92}^{238} U$ and $1$ mol air at $298$ $K$ . Considering complete decay of $_{92}^{238} U$ to $_{82}^{206} P b$ ; the ratio of the final pressure to the initial pressure of the system at $298$ $K$ is: