CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A code word consists of three letters of the English alphabet followed by two digits of the decimal system. If neither letter nor digit is repeated in any code word, then the total number of code words is:

A
1404000
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
16848000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2808000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
157010
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1404000
The first letter of the code can be chosen from the 26 letters in 26 ways. Since no letter is repeated the second letter can chosen in 25 ways and the third letter can be chosen in 24 ways. Similarly there are 10 ways for the first digit and 9 ways for the second digit.
Hence the total number of ways to generate the code is 26×25×24×10×9=14,04,000

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Playing with 2 - Digit and 3 - Digit Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon