A code word consists of two distinct English alphabets followed by two distinct numbers from $1$ to $9$ . For example, AK47 is code word. How many such words are there?
how many of them will end with an even number.

46800, 20800

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44800, 32800

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48800, 32400

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None of these

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Solution

The correct option is A $46800, 20800$
$\begin{matrix} T o t a l e n g l i s h a l p h a b e t s a r e = 26 n o . f r o m 1 t o 9 a r e 9. - - - - - - T o t a l 26 \times 25 \times 9 \times 8 = 26 \times 25 \times 9 \times 8 E n d i t y w i t h e v e n 16 \times 25 \times 8 \times 4 = 20800 \end{matrix}$

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A code word consists of two distinct English alphabets followed by two distinct numbers from 1 to 9. For example, AK47 is code word. How many such words are there?how many of them will end with an even number.

The correct option is A 46800,20800Totalenglishalphabetsare=26no.from1to9are9.−−−−−−Total26×25×9×8=26×25×9×8Enditywitheven16×25×8×4=20800

A code word consists of two distinct English alphabets followed by two distinct numbers from $1$ to $9$ . For example, AK47 is code word. How many such words are there?
how many of them will end with an even number.