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Byju's Answer

Standard X

Physics

Faraday's Experiment

A coil of 30 ...

Question

A coil of 30 turns of wire each of $10 c m^{2}$ area is placed with its plane perpendicular to a magnetic field of $0.1 T .$ When the coil is suddenly withdrawn from the field, a galvanometer connected in series with the coil indicated that a $10 μ C$ charge passes around the circuit. The combined resistance of the coil and galvanometer is:

3 Ω

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30 Ω

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300 Ω

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3000 Ω

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Solution

The correct option is C $300 Ω$

$e m f = \frac{n B A}{t}$
$i = \frac{e m f}{R} = \frac{n B A}{R t}$
$q = i t = \frac{n B A}{R t} t$
$= \frac{n B A}{R}$
$R = \frac{n B A}{q}$
$= \frac{30 \times 0.1 \times 10^{- 3}}{10 \times 10^{- 6}}$
$= 300 Ω$

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The correct option is C 300Ω emf=nBAti=emfR=nBARtq=it=nBARtt=nBARR=nBAq=30×0.1×10−310×10−6=300Ω

The correct option is C $300 Ω$

$e m f = \frac{n B A}{t}$
$i = \frac{e m f}{R} = \frac{n B A}{R t}$
$q = i t = \frac{n B A}{R t} t$
$= \frac{n B A}{R}$
$R = \frac{n B A}{q}$
$= \frac{30 \times 0.1 \times 10^{- 3}}{10 \times 10^{- 6}}$
$= 300 Ω$