Question

A coil of N=100 turns carries a current I=5 A and creates a magnetic flux $\phi ={10}^{-5}T{m}^{-2}$ per turn. The value of its inductance L will be

• A. $0.05mH$
• B. $0.10mH$
• C. $0.15mH$
• D. $0.20mH$

Answer 1

The correct option is D $0.20mH$

$N\varphi =LI$

$N\left(BA\right)=LI$

$100\left({10}^{-5}\right)=L\left(5\right)$

$L=\frac{100}{5}\times {10}^{-5}=\frac{{10}^{-3}}{5}=0.2mH$