Question

A coin is tossed $1000$ times with a frequency of two outcomes: $Head:540,Tail:460$. Find the probability of occurrence of each event.

Answer 1

STEP 1: Defining the two events and writing the formulae for calculation of probability.

The total number of trials (coin tossed) $=1000$

Let $E$and $F$ be the two events of getting head and tail respectively when the coin is tossed.

Number of heads $\left(E\right)=540$

Number of tails $\left(F\right)=460$

Probability of occurrence of heads/tails is given by $P=\frac{Numberofhead/tail}{TotalNumberofTrials}$

STEP 2: Calculating the occurrence of each event

Probability of occurring head when the coin is tossed $P\left(E\right)=\frac{Numberofhead}{Totalnumberoftrials}$

$=\frac{540}{1000}=\frac{27}{50}$

Probability of occurring tail when the coin is tossed $P\left(F\right)=\frac{Numberoftail}{TotalNumberoftrials}$

$=\frac{460}{1000}=\frac{23}{50}$

Hence, the probability of occurring head and tail are $\frac{27}{50}$and $\frac{23}{50}$ respectively.