Question

A coin is tossed $3$ times. The probability of getting head and tail alternately is

• A. $\frac{1}{8}$
• B. $\frac{1}{2}$
• C. $\frac{1}{4}$
• D. $\frac{1}{6}$

Answer 1

The correct option is C $\frac{1}{4}$

Total possibilities $=2\ast 2\ast 2=8$
Favorable cases $=2=\left[HTH,THT\right]$
$\Rightarrow P=2/8=1/4$