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Question

A coin is tossed 6 times, in how many throws can 4 heads and 2 tails be obtained?


A

24

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B

10

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C

15

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D

18

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Solution

The correct option is B

10


Total throws = 6
Oou of 6, 4 throws should give one type of outcome and 2 of another type.
So required number
=6!/[4!*2!]
=15


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