A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of same sol is studied using $N a C l$ , $B a {C l}_{2}$ and $A l {C l}_{3}$ solutions. Their coagulation power should be :

N a C l > B a {C l}_{2} > A l {C l}_{3}

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B a {C l}_{2} > A l {C l}_{3} > N a C l

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A l {C l}_{3} > B a {C l}_{2} > N a C l

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B a {C l}_{2} > N a C l > A l {C l}_{3}

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Solution

The correct option is C $A l {C l}_{3} > B a {C l}_{2} > N a C l$
Hardy Schulze Law: The effective ions of the electrolytes in bringing about coagulation are those which carry a charge opposite to that of colloidal particles. Greater the valency of coagulating or fluctuating ion, greater is its power to bring about coagulation.

When colloidal solution is subjected to electrical field, coagulating power should be in the order of $A l {C l}_{3} > B a {C l}_{2} > N a C l$ as thier valency is increasing.

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A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of same sol is studied using NaCl, BaCl2 and AlCl3 solutions. Their coagulation power should be :

A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of same sol is studied using $N a C l$ , $B a {C l}_{2}$ and $A l {C l}_{3}$ solutions. Their coagulation power should be :