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Question

A company produces three products every day. Their production on a certain day is 45 tons. It is found that the production of third product exceeds the production of first product by 8 tons while the total production of first and third product is twice the production of second product. Determine the production level of each product using matrix method.

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Solution

Let x, y and z be the production level of the first, second and third product, respectively.

According to the question,x+y+z=45 ...(1)-x+z=8 ...(2)x+z=2y Since the production of first and third product is twice the production of second productx-2y+z=0 ...(3)The given system of equation can be written in matrix form as follows: 111-1011-21xyz=4580AX=BA= 111-1011-21 X=xyz B=4580Now, A=1 -0+2-1-1-1+12-0=2+2+2=6Let Cij be the cofactors of the elements aij in A=aij. Then,C11=-11+101-21=2, C12=-11+2-1111=2, C13=-11+3 -101-2=2C21=-12+111-21=-3, C22=-12+21111=0, C23=-12+3111-2=3C31=-13+11101=1, C32=-13+211-11=-2, C33=-13+311-10=1adj A=222-3031-21T = 2-3120-2231A-1=1Aadj A=162-3120-2231X=A-1BX=162-3120-22314580X=1690-24+090+0+090+24+0xyz=166690114 x=11, y=15 and z=19Thus, the production level of first, second and third product is 11, 15 and 19, respectively.

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