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Van't Hoff Factor

A complex con...

Question

A complex containing K $^{+}$ , Pt(IV) and Cl $^{-}$ is 100% ionised giving $i =$ 3. Thus, the complex is :

A

K_{2} [P t C l_{4}]

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B

K_{2} [P t C l_{6}]

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C

K_{3} [P t C l_{5}]

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D

K [P t C l_{3}]

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Solution

The correct option is B $K_{2} [P t C l_{6}]$
i $=$ van,t Hoff factor $= 1 + (y - 1) α$ (y $=$ number of ions, $α =$ degree of ionisation)
(1) $K_{2} P t C l_{4} \to 2 K^{+} + [P t C l_{4}]^{2 -};$ $i = 1 + 2 = 3$
(2) $K_{2} P t C l_{6} \to 2 K^{+} + [P t C l_{6}]^{2 -};$ $i = 1 + 2 = 3$
In (1), oxidation number of $P t$ $=$ 2
In (2), the oxidation number of $P t$ $=$ 4
Therefore, $K_{2} [P t C l_{6}]$ is the correct answer.

Option B is correct.

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Similar questions

p K

value of the complex

[P t C l_{4}]

P t^{4 +} + C l^{-} \to [P t C l]^{3 +}

K_{1} = 10^{- 2}

[P t C l]^{3 +} + C l^{-} \to [P t C l_{2}]^{2 +}

K_{2} = 10^{- 3}

[P t C l_{2}]^{2 +} + C l^{-} \to [P t C l_{3}]^{+}

K_{3} = 10^{- 4}

[P t C l_{3}]^{+} + C l^{-} \to [P t C l_{4}]

K_{4} = 10^{- 4}

Q. Among the following complexes (K-P) :

K_{3} [F e (C N_{6}] - K

[C o (N H_{3})_{6}] C l_{3} - L

N a_{3} [C o (o x a l a t e)_{3}] - M

[N i (H_{2} O)_{6}] C l_{2} - N

K_{2} [P t (C N)_{4}] - O

[Z n (H_{2} O)_{6}] (N O_{3})_{2} - P

;
the diamagnetic complexes are:

Q. Combination of

P t (I V), N H_{3}, C l^{-}, K^{+}

result in the formation of

x

complexes and one such complex is

[P t (N H_{3})_{6}] C l_{4}

x

Q. Among the following complexes

(K - P) K_{3} [F e (C N)_{6} (K), [C o (N H_{3})_{6}] C l_{3} (L), N a_{3} [C o (o x a l a t e)_{3}] (M), [N i (H_{2} O)_{6}] C l_{2} (N), K_{2} [P t (C N)_{4}] (O) and [Z n (H_{2} O)_{6}] (N O_{3})_{2} (P)

. The diamagnetic complexes are-

Q. The complexes

[P t {(N H_{3})}_{4}] [P t C l_{6}]

[P t {(N H_{3})}_{4} C l_{2}] [P t C l_{4}]

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