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Standard X

Chemistry

Laboratory Preparation of Ammonia

A compound A ...

Question

A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
(E) dissolves in warm concentrated HCl to give a yellow solution (F).
what is F?

F e C l_{3}

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F e C l_{2}

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F e C l

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None of these

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Solution

The correct option is A $F e C l_{3}$
The compound (A) is hydrated ferric sulphate (green vitriol) $F e S O_{4} \cdot 7 H_{2} O$
$2 F e S O_{4} Δ - \to S O_{2} ↑ + S O_{3} ↑ + F e_{2} O_{3}$
The compound E is ferric oxide ( $F e_{2} O_{3}$ ).
It dissolves in warm conc. HCl to give a yellow solution (F) .The solution (F) is ferric chloride $F e C l_{3}$
$F e_{2} O_{3} + 6 H C l (warm conc) \to 2 F e C l_{3} + 3 H_{2} O$

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Q. A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
(E) dissolves in warm concentrated HCl to give a yellow solution (F).

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On heating (A), water vapors and two oxides of sulphur, (C) and (D) are liberated leaving a red-brown residue (E).

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A compound (A) is greenish crystalline salt which gave the following results : On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E). (E) dissolves in warm concentrated HCl to give a yellow solution (F). what is F?

A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
(E) dissolves in warm concentrated HCl to give a yellow solution (F).
what is F?