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Standard XII
Chemistry
Chemical Reactivity (Group 1)
Compound A is...
Question

Compound (A) is a greenish crystalline salt which gives the following results when tested :

(a) Addition of BaCl2 solution to a solution of (A) results in the formation of a white precipitate (B) which is insoluble in dilute HCl.

(b) On heating, water vapour and two gases (C) and (D) are liberated, leaving a red brown residue (E).

(c) (E) dissolves in conc.HCl to give a yellow solution (F).

(d) With H2S, the solution (F) yields a yellow-white ppt. (G) which when filtrated, leaves a greenish filtrate (H).

(e) The solution (F) gives a green solution with SnCl2, and when reacted with K4[Fe(CN)6] gives a blue ppt.

Identify yellow solution, (F).

A
Fe2O3
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B
FeCl3
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C
ZnCl2
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D
CuCl
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Solution

The correct option is B FeCl3
(A) is FeSO4⋅7H2O
FeSO4+BaCl2⟶BaSO4↓+FeCl2(B)
2FeSO4Δ−→Fe2O3+SO2+SO3(E)(C)(D)
Fe2O3+6HCl⟶2FeCl3+3H2O(F)
2FeCl3+H2S⟶2FeCl2+2HCl+S(H)(G)
2FeCl3+SnCl2⟶2FeCl2+SnCl4
4FeCl3+3K4Fe(CN)6⟶Fe4[Fe(CN)6]3+13KClPrussianBlue
(FeCl3 gives blood red colouration with thiocyanate ion.)
FeCl3+3KSCN⟶Fe(SCN)3+3KClPotassiumBloodredthiocyanatecoloration

Therefore, from above solution, option B is correct.

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