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Standard XII

Chemistry

Conductivity MP BP and Electronegativity (Group 2)

A compound A ...

Question

A compound (A) is greenish crystalline salt which gave the following results :
On heating (A), water vapours and two oxides of sulfur, (C) and (D) are liberated leaving a red-brown residue (E).
(E) dissolves in warm concentrated HCl to give a yellow solution (F).
With H $_{2}$ S, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H).
What is compound H?

F e C l_{2}

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F e C l_{3}

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F e_{2} C l_{4}

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None of these

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Solution

The correct option is A $F e C l_{2}$
The compound (A) is hydrated ferric sulphate (green vitriol) $F e S O_{4} \cdot 7 H_{2} O$
$2 F e S O_{4} Δ - \to S O_{2} ↑ + S O_{3} ↑ + F e_{2} O_{3}$
The compound E is ferric oxide ( $F e_{2} O_{3}$ ).
$F e_{2} O_{3} + 6 H C l (warm conc) \to 2 F e C l_{3} + 3 H_{2} O$
With $H_{2} S$ , the solution (F) (ferric chloride $F e C l_{3}$ ) yields a pale yellow ppt. (G) of S, which when filtered, leaves a greenish filtrate (H) of $F e C l_{2}$ . The compound H is $F e C l_{2}$ .
$2 F e C l_{3} + H_{2} S \to 2 F e C l_{2} + 2 H C l + S$

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