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Byju's Answer

Standard XII

Chemistry

Borax

A compound ...

Question

A compound $A$ of boron reacts with $N M e_{3}$ to give an adduct $B$ which on hydrolysis gives a compound $C$ and a gas $D$ . Compound $C$ is an acid.

Compound $A$ is :

diborane

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boric acid

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borate salt

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none of these

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Solution

The correct option is A diborane
$B_{2} H_{6} + 2 N M e_{3} ⟶ 2 B H_{3} . N M e_{3}$
Diborane (A) Adduct (B)

$B H_{3} . N M e_{3} + 3 H_{2} O ⟶ H_{3} B O_{3} + N M e_{3} + 3 H_{2}$
Boric acid $↓$
(C) (D) gas
Compound $A$ is diborane.

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Similar questions

A compound

A

of boron reacts with

N M e_{3}

to give an adduct

B

which on hydrolysis gives a compound

C

and a gas

D

. Compound

C

is an acid.

Compound

C

is :

Q. An organic compound

A

with molecular formula

C_{3} H_{6} O

is resistant to oxidation but forms compound

B

C_{3} H_{8} O

on reduction, compound

B

reacts with

H B r

from

C

and

C

reacts with

M g

from Grignard reagent.

D

reacts with

A

to form a product which on hydrolysis gives

E

. Identify

A, B, C, D, E

Q. Compound 'A' on chlorination gives compound 'B', compound 'B' reacts with alc. KOH gives gas 'C', which decolourizes Baeyer's reagent and ozonolysis of compound 'C' gives only HCHO compound. Then compound 'A' is:

Q. An organic compound (A) gives positive Liebermann reaction and on treatment with

C H C l_{3} / K O H

followed by hydrolysis gives (B) and (C) ,. Compound (B) gives colour with Schiff's reagent but not (C), which is steam - volatile. (C) on treatment with

L I A l H_{4}

gives (D),

C_{7} H_{8} O_{2}

which on oxidation gives 9E), Compound (E) reacts with

{(C H_{3} C O)}_{2} O / C H_{3} C O O H

to give a pain - reliever (F), Give structure of (A) to (F) with proper reasoning.

Q. Calcium imide on hydrolysis gives a gas

B

, which on oxidation by bleaching powder gives a gas

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A compound A of boron reacts with NMe3 to give an adduct B which on hydrolysis gives a compound C and a gas D. Compound C is an acid.Compound A is :

The correct option is A diborane B2H6+2NMe3⟶2BH3.NMe3Diborane (A) Adduct (B)BH3.NMe3+3H2O⟶H3BO3+NMe3+3H2 Boric acid ↓ (C) (D) gasCompound A is diborane.

A compound $A$ of boron reacts with $N M e_{3}$ to give an adduct $B$ which on hydrolysis gives a compound $C$ and a gas $D$ . Compound $C$ is an acid.

Compound $A$ is :

The correct option is A diborane
$B_{2} H_{6} + 2 N M e_{3} ⟶ 2 B H_{3} . N M e_{3}$
Diborane (A) Adduct (B)

$B H_{3} . N M e_{3} + 3 H_{2} O ⟶ H_{3} B O_{3} + N M e_{3} + 3 H_{2}$
Boric acid $↓$
(C) (D) gas
Compound $A$ is diborane.