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Question

A compound (A) of boron reacts with NMe3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A,B and C. Give the reactions involved.

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Solution

As per the question,

A+NMe3B

B is an adduct.

On hydrolysis,

B+H2OC+H2(g)

Also stated that C is acidic in nature.

Formation of adduct
  • Diborane undergoes cleavage reactions with Lewis bases such as Trimethyl nitrogen N(Me)3 to give borane adducts, BH3NMe3
  • It is an addition compound of borane and Lewis base.
B2H6+2NMe32BH3NMe3
  • Therefore, A is diborane (B2H6).
  • B is adduct or addition compound called borane adduct i.e. BH2NMe3

Adduct to acid conversion

Compound B on hydrolysis gives boric acid, H3BO3

The reaction is:

BH3NMe3+3H2OH3BO3+NMe3+3H2

Therefore, the compound C is orthoboric acid (H3BO3) which is not a protonic acid but acts as a Lewis acid.

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