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Question

A compound C (molecular formula, C2H4O2) reacts with Na metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S (molecular formula, C3H6O2). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A.
Identify R and A?

A
Compound R is CH3COONa
Compound A is CH3OH
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B
Compound A is CH3OH
Compound R is CH3COOCH3
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C
Compound A is CH3COOH
Compound R is CH3COONa
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D
Compound A is CH3COONa
Compound R is CH3OH
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Solution

The correct option is A Compound R is CH3COONa
Compound A is CH3OH
Compound C is CH3COOH.
Compound R is CH3COONa.
Compound A is CH3OH.
Compound S is CH3COOCH3.
Chemical reactions in sequence are as follows:
(a) 2CH3COOH+2Na2CH3COONa+H2
(C) (R)

(b) CH3COOH+CH3OHConc.H2SO4−−−−−−−CH3COOCH3+H2O
(C) (A) (S)

(c) CH3COOOH+NaOHCH3COONa+H2O
(C) (R)

(d) CH3COOCH3+NaOHCH3COONa+CH3OH
(R) (A)

Option A is correct.

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