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Empirical & Molecular Formula

A compound co...

Question

A compound contains $C = 90$ % and $H = 10$ %. Empirical formula of the compound is :

C_{15} H_{30}

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C_{15} H_{20}

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C_{3} H_{4}

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C_{3} H_{10}

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Solution

The correct option is C $C_{3} H_{4}$
$\begin{matrix} C & : & H \frac{90}{12} & : & \frac{10}{1} = 7.5 & : & 10 = 1 & : & 1.3 = 3 & : & 4 \end{matrix}$ $\begin{matrix} \end{matrix}$
Therefore, the empirical formula is $= C_{3} H_{4}$ .

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