A compound has an empirical formula of C₂HBr. If the molar mass of the compound is 314.7 g/mol, what is the molecular formula of the compound? (Atomic mass of Br = 80g/mol)

C₄H₂Br₂

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C₂HBr

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C₈H₄Br₄

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C₆H₃Br₃

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Solution

The correct option is D
C₆H₃Br₃

Empirical formula mass is (2 X 12) + 1 + 80 = 105g and molar mass of the compound is 314 g/mol.

Hence, n = 3

Therefore, the molecular formula is C₆H₃Br₃.

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