A compound is formed by two elements $P$ and $Q$ . Atoms of $Q$ (as anions) make hcp lattice and those of the element $P$ (as cations) occupy all the tetrahedral voids. What is the formula of the compound?

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Solution

Let number of atoms of $Q$ in lattice is $x$
Number of tetrahedral voids $= 2 \times$ no. of atoms in hcp.
So number of atoms of $P$ In lattice is 2. Hence chemical formula of the compound will be $P_{2 x} Q_{x} = P_{2} Q$

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A compound is formed by two elements P and Q. Atoms of Q (as anions) make hcp lattice and those of the element P (as cations) occupy all the tetrahedral voids. What is the formula of the compound?

Let number of atoms of Q in lattice is xNumber of tetrahedral voids =2× no. of atoms in hcp.So number of atoms of P In lattice is 2. Hence chemical formula of the compound will be P2xQx=P2Q

A compound is formed by two elements $P$ and $Q$ . Atoms of $Q$ (as anions) make hcp lattice and those of the element $P$ (as cations) occupy all the tetrahedral voids. What is the formula of the compound?

Let number of atoms of $Q$ in lattice is $x$
Number of tetrahedral voids $= 2 \times$ no. of atoms in hcp.
So number of atoms of $P$ In lattice is 2. Hence chemical formula of the compound will be $P_{2 x} Q_{x} = P_{2} Q$