Question

A compound is made of $Ba$ (oxidation number $=+2$), $Xe$ (oxidation number $=8$) and oxygen. $Xe$ and $O$ are present in the atomic ratio of $1:6$, the compound is:

• A. ${Ba}_{2}Xe{O}_6$
• B. ${Ba}_{2}X{e}_2{O}_6$
• C. ${Ba}_{3}Xe{O}_5$
• D. none of these

Answer 1

The correct option is A ${Ba}_{2}Xe{O}_6$

$Ba$ $Xe$ $O$
$n:1:6$ ratio
Let $n$ be the number of Ba atoms.
Since the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
$2n+8-12=0$
$n=2$
$\therefore$ The compound is ${Ba}_{2}Xe{O}_6$.