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Standard XII

Chemistry

Decarboxylation Reaction of Alkanes

A compound is...

Question

A compound is treated with $N a N H_{2}$ to give sodium salt. Identify the compound.

C_{2} H_{2}

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C_{6} H_{6}

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C_{2} H_{6}

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C_{2} H_{4}

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Solution

The correct option is A $C_{2} H_{2}$
Only $C_{2} H_{2}$ (acetylene) has acidic H-atoms and hence reacts with $N a N H_{2}$ to form sodium salt, i.e.,

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Similar questions

Q. This compound forms a sodium salt upon reacting with

N a N H_{2}

. Identify the compound.

Q. Compound '

A

' (molecular formula

C_{3} H_{8} O

is treated with acidified potassium dichromate to form a product '

B

' (molecular formula

C_{3} H_{6} O

). '

B

' forms a shining silver mirror on warming with ammoniacal silver nitrate. '

B

' when treated with an aqueous solution of

H_{2} N C O N H N H_{2}

and sodium acetate gives a product '

C

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Q. A compound of sodium does not give

C O_{2}

when heated but it gives

C O_{2}

when treated with dilute acids. A crystalline compound is found to have 37.1% Na and 14.52%

H_{2} O

. Hence, the compound is :

Q. When metal

X

is treated with sodium hydroxide, a white precipitate

(A)

is obtained, which is soluble in excess of

N a O H

to give soluble complex

(B)

Compound

(A)

is soluble in dilute

H C l

to form compound

(C)

. The compound

(A)

when heated strongly gives

(D)

, which is used to extract metal.

Identify

(X), (A), (B), (C)

and

(D)

. Write suitable equations to support their identities:

An aqueous solution of a salt (A) gives white precipitate (B) with sodium chloride solution. The filtrate gives a black precipitate. (C) When $H_{2} S$ is passed into it. Compound (B) dissolves in hot water and the solution gives a yellow precipitate (D) on treatment with sodium iodide. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Identify the compound (A) to (D).

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A compound is treated with NaNH2 to give sodium salt. Identify the compound.

The correct option is A C2H2Only C2H2 (acetylene) has acidic H-atoms and hence reacts with NaNH2 to form sodium salt, i.e.,

A compound is treated with $N a N H_{2}$ to give sodium salt. Identify the compound.

The correct option is A $C_{2} H_{2}$
Only $C_{2} H_{2}$ (acetylene) has acidic H-atoms and hence reacts with $N a N H_{2}$ to form sodium salt, i.e.,