1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# An aqueous solution of a salt (A) gives white precipitate (B) with sodium chloride solution. The filtrate gives a black precipitate. (C) When H2S is passed into it. Compound (B) dissolves in hot water and the solution gives a yellow precipitate (D) on treatment with sodium iodide. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Identify the compound (A) to (D).

A

A=Pb(NO3)2 B=PbCl2 C=PbS D=Pbl2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

A=PbSO3 B=PbCl2 C=PbCl D=PbO2

No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C

A=Pbl2 B=PbO C=PbH4 D=Pb(NO3)2

No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D

A=PbS B=PbCl2 C=Pb(NO3)2 D=Pbl2

No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is A A=Pb(NO3)2 B=PbCl2 C=PbS D=Pbl2 Since the crystalline compound (B) dissolves in hot water and gives a yellow precipitate withNaI, it should be lead chloride, PbCl2 and the solution (A) consists a lead salt. PbCl2+2Nal(→)Pbl2+2NaCl (B) (D) The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating, it should be lead nitrate, Pb(NO3)2 2Pb(NO3)2(→)2PbO+2NO2+O2 (A) Reddish brown gas Lead chloride is sparingly soluble in water.When H2S is passed, it gives a black precipitate of lead sulphide, PbS. PbCl2+H2S(→)PbS+2HCl Black Thus A) is lead nitrate, Pb(NO3)2B)is lead chloride, PbCl2 C) is lead Sulphide, PbSD) is lead Iodide, Pbl2

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Compounds of Lead
CHEMISTRY
Watch in App
Explore more
Join BYJU'S Learning Program