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A compound mi...

Question

A compound microscope consists of an objective lens with focal length 1.0 cm and eye piece of focal length 2.0cm and a tube length 20cm the magnification is

A

100

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B

200

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C

250

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D

300

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Solution

The correct option is A 250
Magnification, of compound microscope
$m = m_{0} \times m_{e} = (\frac{L}{f_{0}} \times \frac{D}{f_{e}})$
Here, L = 20 cm, D = 25 cm (near point), $f_{0}$ = 1 cm and $f_{e}$ = 2 cm
$∴ m = \frac{20}{1} \times \frac{25}{2}$ = 250

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