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Introduction to Alcohols

A compound of...

Question

A compound of B (Boron), X reacts at $200^{\circ} C$ with $N H_{3}$ to give another compound Y which is called as inorganic benzene. The compound Y is colorless liquid and is highly light sensitive. The compound X with excess of $N H_{3}$ and at still higher temp gives $(B N)_{n}$ . The compound X and Y respectively.

A

$B H_{3}$ and $B_{2} H_{6}$

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B

$N a B H_{4}$ and $C_{6} H_{6}$

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C

$B_{2} H_{6}$ and $B_{3} N_{3} H_{6}$

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D

$B_{4} C_{3}$ and $C_{6} H_{6}$

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Solution

The correct option is C
$B_{2} H_{6}$ and $B_{3} N_{3} H_{6}$

$3 B_{2} H_{6} + 6 N H_{3} \to 2 B_{3} N_{3} H_{6} + 12 H_{2}$

$B_{2} H_{6} + N H_{3} (excess) \to (B N)_{n} + H_{2}$

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Similar questions

Q. A compound of boron X reacts at

200^{\circ} C

temperature with

N H_{3}

to give another compound

Y

which is called as inorganic benzene. The compound

Y

is a colourless liquid and is highly sensitive. Its melting point is

- 57^{\circ} C

X

N H_{3}

and at a still higher temperature gives boron nitride

{(B N)}_{n}

. The compounds

X

Y

respectively are:

Q. A compound of boron X reacts at

200^{\circ} C

temperature with

N H_{3}

to give another compound

Y

which is called as inorganic benzene. The compound

Y

is a colourless liquid and is highly sensitive. Its melting point is

- 57^{\circ} C

X

N H_{3}

and at a still higher temperature gives boron nitride

{(B N)}_{n}

. The compounds

X

Y

respectively are:

X

, of boron reacts with

N H_{3}

on heating to give another compound

Y

which is called inorganic benzene. The compound

X

can be prepared by treating

B F_{3}

with lithium aluminum hydride. The compounds

X

Y

are represented by formula:

N a_{2} B_{4} O_{7} .10 H_{2} O 720^{o} C - --- \to Δ 2 N a B O_{2} + (X) + 10 H_{2} O

(X) + C a F_{2} + H_{2} S O_{4} ⟶ (Y) + C a S O_{4} + H_{2} O

(Y) + N a B H_{4} ⟶ (Z) + N a B F_{4}

(Z) High temperature - --------- \to N H_{3} (1 : 2) B_{3} N_{3} H_{6} Inorganic benzene

Select the correct statements regarding compound

(X), (Y)

(Z)

.

Q.
Primary alkyl halide

C_{4} H_{9} B r

(X) reacts with alc.

K O H

to give compound (Y). Compound (Y) reacts with

H B r

to give compound (Z) which is an isomer of (X). When (X) react with Na metal it gives compound (P).

Hence compound (X), (Y), (Z) and (P) respectively are :

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