A compound of relative molecular mass 34 and empirical formula $H O$ has the molecular formula :

H O_{2}

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H O

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H_{2} O

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H_{2} O_{2}

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Solution

The correct option is D $H_{2} O_{2}$
Empirical formula mass is $1 + 16 = 17$
The ratio of the molecular formula mass to the empirical formula mass is $\frac{34}{17} = 2$
therefore ,n=2
Molecular formula =Empirical formula $\times$ n
= 17 $\times$ 2
Hence, the molecular formula is obtained by multiplying empirical formula with $2$ . The molecular formula is $H_{2} O_{2}$ .

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Similar questions

Q. A compound of relative molecular mass 34 and empirical formula HO has the molecular formula ___________.

State whether the given statement is true or false:

A compound of relative molecular mass

34

and empirical formula

H O

has the molecular formula

H_{2} O_{2}

(a) Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen (O = 16; Na = 23; Si = 28).
(b) The empirical formula of a compound is C₂H₅. It has a vapour density of 29. Determine the relative molecular mass of the compound and hence its molecular formula.

Q. Which of the following statements about molecular and empirical formulas is\ are false?
I. A given compound can have the same, molecular and empirical formula.
II. The molecular formula is a whole number multiple of the empirical formula.
III.

H_{2} O_{2}

represents the empirical formula of hydrogen peroxide.

Q. Empirical formula of a compound is

C H_{2} O

and its molecular mass is

90

, the molecular formula of the compound is :

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A compound of relative molecular mass 34 and empirical formula HO has the molecular formula :

A compound of relative molecular mass 34 and empirical formula $H O$ has the molecular formula :