Question

A compound of vanadium has a magnetic moment of 1.73 BM. Vanadium chloride has the formula:

• A. $VC{l}_2$
• B. $VC{l}_3$
• C. $VC{l}_4$
• D. $VC{l}_5$

Answer 1

The correct option is C $VC{l}_4$

Magnetic moment is given by, $\mu =\sqrt{n(n+2)}$
where $n$ is the number of unpaired electron.
Given: $\mu =1.73BM$
$\therefore \mu =\sqrt{n(n+2)}=1.73$
$\Rightarrow n=1$
Since only one unpaired electron is there, the ion is $V^{4+}$ and its chloride is $VC{l}_4$.