Question

A compound of Xe and F is found to have 53.4% Xe (atomic mass = 133). Oxidation number of Xe in this compound is____.

• A. 0.0
• B. 2
• C. 4
• D. 6

Answer 1

The correct option is D 6

$\begin{array}{ccc}Xe& :& F\\ \frac{53.4}{133}& & \frac{46.6}{19}\\ 0.401& :& 2.45\\ 1& :& 6\end{array}$

Thus, the empirical formula is $Xe{F}_6$.

$\therefore$ O, N. of Xe in $Xe{F}_6=+6$