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Question

A compound of Xe and F is found to have 53.5% of Xe. What is oxidation number of Xe in this compound?

A
4
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B
0
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C
+4
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D
+6
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Solution

The correct option is D +6
A compound of Xe and F is found to have 53.5% of Xe.
100 g of this compound will have 53.5 g of Xe and 46.5 g of F.
The atomic masses of Xe and F are 131.2 g/mol and 19 g/mol respectively.
The number of moles of Xe=53.5131.2=0.4
The number of moles of F=46.519=2.4
The mole ratio Xe:F=0.4:2.4=1:6
Molecular formula of the compound is XeF6
Let n be the oxidation number of Xe in XeF6
The oxidation number of F is 1
n+6(1)=0
n6=0
n=6
The oxidation number of Xe in XeF6 is +6

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