MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Classification

A compound re...

Question

A compound responds to Baeyer's test but does not give white precipitation when treated with ammonical silver nitrate solution the compound should be:

A

C_{2} H_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

C_{3} H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

C_{2} H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

C_{2} H_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $C_{2} H_{4}$
A compound responds to Baeyer's test but does not give white precipitation when treated with ammonical silver nitrate solution the compound should be ethylene $C_{2} H_{4}$ .

Alkene & alkyne both give positive Baeyer's test but only terminal alkynes, and not alkenes, give positive test with ammonical silver nitrate [Tollen's reagent].

Suggest Corrections

thumbs-up

0

Similar questions

Q. Chloroform is a chlorine compound, but it does not give white precipitate with silver nitrate solution. Give reasons.

^{'} A^{'}

is treated with a freshly prepared ammonical silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline soild on treatment with sodium hydrogensulphit. Liquid

^{'} B^{'}

also forms a white crystalline solid with sodium hydrogensulphite but it does not give test with ammoniacal silver nitrate. Which of the two liquids is aldehyde? Write the chemical equations of these reactions also.

Q. Which of the following compound gives silver mirror tests on treatment with ammonical silver nitrate solutions?

Q. An unknown compound 'A' has a molecular formula

C_{4} H_{6}

. When A is treated with an excess of

B r_{2}

a new substance B with formula

C_{4} H_{6}

B r_{2}

is formed. 'A' forms a white precipitate with ammonical silver nitrate solution. A may be :

Q. An unknown compound (A) has a molecular formula

C_{4} H_{6} .

When (A) is treated with excess of

B r_{2} / C C l_{4}

a new compound (B) with formula

C_{4} H_{6} B r_{4}

is formed. (A) forms a white ppt. with ammonical silver nitrate solution. The compound (A) is :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Classification of Halocompounds

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon