A compound with molecular mass 180 is acylated with CH3COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is
A
5
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B
6
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C
4
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D
2
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Solution
The correct option is A5 R−NH2M+CH3COCl⟶RNHCOCH3M+42+HCl
If the increase in molecular mass is 42, the reactant has one NH2 group.
Actual increase in molecular mass =390–180 =210
Number of NH2 groups =21042=5