Question

A compound $\left(x\right)$ on treatment with $Na$ gives $\left(y\right)$, and with $PC{l}_5$ gives $\left(z\right)$.$\left(y\right)$ and $\left(z\right)$ react together to form diethyl ether.
$\left(x\right),\left(y\right)$ and $\left(z\right)$ respectively are:

• A. $C_2{H}_{5}OH,C_2{H}_6,C_2{H}_{5}Cl$
• B. $C_2{H}_{5}OH,C_2{H}_{5}Cl,C_2{H}_{5}ONa$
• C. $C_2{H}_{5}Cl,C_2{H}_6,C_2{H}_{5}OH$
• D. $C_2{H}_{5}OH,C_2{H}_{5}ONa,C_2{H}_{5}Cl,$

Answer 1

The correct option is D $C_2{H}_{5}OH,C_2{H}_{5}ONa,C_2{H}_{5}Cl,$

$\underset{x}{C_2{H}_{5}OH}\stackrel{Na}{\to }\underset{y}{C_2{H}_{5}ONa}$

$\underset{x}{C_2{H}_{5}OH}\stackrel{PC{l}_5}{\to }\underset{z}{C_2{H}_{5}Cl}$

$\underset{y}{C_2{H}_{5}ONa}+\underset{z}{C_2{H}_{5}Cl}\to C_2{H}_{5}O{C}_2{H}_5$