The correct option is B 20 cm
Given:
f=−20 cm
Here, the magnitude of magnification is 2.
|m|=2
⇒m=±2
⇒m=ff−u
⇒±2=−20−20−u
⇒−20−u=±10
⇒u=−20±10
⇒u=−10 cm or −30 cm
Hence, the distance of the object may be 30 cm or 10 cm.
So, the distance between the two positions of the object =30−10=20 cm
Why this question?Magnification is possible for both real and virtual images.