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Relationship between Focus and Radius of Curvature

A concave mir...

Question

A concave mirror is half dipped in water. Focal length of portion of mirror is the air is $f_{1}$ and focal length of mirror in water is $f_{2}$ , then (Take refractive index of water $= \frac{4}{3}$ )

f_{1} > f_{2}

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f_{1} < f_{2}

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f_{1} = f_{2}

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f_{1} \geq \frac{4}{3} f_{2}

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Solution

The correct option is D $f_{1} = f_{2}$
The focal length of a mirror is function of its radius of curvature and is independent of the medium as it is based on the lows of reflection. So the focal length $f$ , remains same in every medium.

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