A concave mirror of radius of curvature 40 cm forms an image of an object placed on the principal axis at a distance 45 cm in front of it. Now if the system (including object) is completely immersed in water $(μ = 1.33)$ , then:

the image will shift towards the mirror.

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the magnification will reduce.

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the image will shift away from the mirror and magnification will increase.

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the position of the image and magnification will not change.

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Solution

The correct option is B the position of the image and magnification will not change.
Mirror operates on the principle of Laws of reflection.
Therefore, focal length does not depend upon the medium and object distance is also unchanged, so their will be no change in the image distance, correspondingly magnification will also remain unchanged.

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A concave mirror of radius of curvature 40 cm forms an image of an object placed on the principal axis at a distance 45 cm in front of it. Now if the system (including object) is completely immersed in water (μ=1.33), then:

A concave mirror of radius of curvature 40 cm forms an image of an object placed on the principal axis at a distance 45 cm in front of it. Now if the system (including object) is completely immersed in water $(μ = 1.33)$ , then: