A concrete gravity dam section is shown in the figure. Assuming unit weight of water as $10 k N / m^{3}$ and unit weight of concrete as $24 k N / m^{3}$ the uplift force per unit length of the dam (expressed in kN/m) at PQ is

16250

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32500

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21000

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10500

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Solution

The correct option is D 10500

$\Rightarrow F = \frac{1}{2} \times 10 (65 + 25) \times 10 + \frac{1}{2} (25 + 5) \times 40 \times 10$

= 4500 + 6000

F = 10500 kN/m

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A concrete gravity dam section is shown in the figure. Assuming unit weight of water as 10 kN/m3 and unit weight of concrete as 24 kN/m3 the uplift force per unit length of the dam (expressed in kN/m) at PQ is

The correct option is D 10500 ⇒F=12×10(65+25)×10+12(25+5)×40×10 = 4500 + 6000 F = 10500 kN/m

A concrete gravity dam section is shown in the figure. Assuming unit weight of water as $10 k N / m^{3}$ and unit weight of concrete as $24 k N / m^{3}$ the uplift force per unit length of the dam (expressed in kN/m) at PQ is

The correct option is D 10500

$\Rightarrow F = \frac{1}{2} \times 10 (65 + 25) \times 10 + \frac{1}{2} (25 + 5) \times 40 \times 10$

= 4500 + 6000

F = 10500 kN/m