Question

A condenser and a 30 $\Omega$ resistance are connected in series. When they are connected to 120V A.C. source then the current flowing in the circuit is 1A The p.d. across the ends of the condenser will be nearly

• A. 1 V
• B. 116 V
• C. zero
• D. 220 V

Answer 1

The correct option is B 116 V

$i=\frac{V}{Z}$

$Z=\frac{V}{i}=\frac{120}{1}=120\Omega$

$Z=\sqrt{R^2+X_C^2}$

$(120{)}^2=(30{)}^2+X_C^2$

$X_C^2=13500$

$X_C=116\Omega$

$V_C=i{X}_C$

$=1\left(116\right)$

$=116V$