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Equivalent, Molar Conductivity and Cell Constant

A conductance...

Question

A conductance cell was calibrated by filling it with a $0.02 M$ solution of potassium chloride (specific conductance $= 0.2768 o h m^{- 1} m^{- 1}$ ) and measuring the resistance at $298 K$ which was found to be $457.3 o h m$ . The cell was then filled with a calcium chloride solution containing $0.555 g$ of $C a C l_{2}$ per litre. The measure resistance was $1050 o h m$ . Calculate the molar conductivity of $C a C l_{2}$ solution.

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Solution

Determine cell constant with $K C l$ data. Its value is $126.6 m^{- 1}$ .
Sp. cond. of $C a C l_{2} s o l n . = C e l l c o n s t . \times \frac{1}{R e s i s t a n c e}$
$= 126.6 \times \frac{1}{1050} = 0.1206 o h m^{- 1} m^{- 1}$
Molar conductance $= \frac{S p . c o n d .}{C o n c .}$
$C o n c . = \frac{0.555}{111.0} = 0.005 m o l d m^{- 3} = 5 m o l m^{- 3}$ .

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