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Question

A conducting rod of Length L=0.1m is moving with a uniform speed v=0.2 m/s on conducting rails in a magnetic field B=0.5T as shown. On one side, the end of the rails is connected to a capacitor of capacitance C=20μF. Then the charges on the capacitor plates are.
810442_e6a23393e60c48828d0e14786a75164b.png

A
qA=0=qB
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B
qA=+20μC and qB=20μC
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C
qA=+0.2μC and qB=0.2μC
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D
qA=0.2μC and qB=+0.2μC
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Solution

The correct option is C qA=+0.2μC and qB=0.2μC
L=0.1m , v=0.2ms1 ,B=0.5T ,C=20μF
V=BvL
=0.5×0.2×0.1=0.01
q=cv=20μF×0.01=0.2μC
qA=+0.2μC
qB=0.2μC

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