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Question

A conducting rod PQ of length L=1.0 m is moving with a uniform speed V=2.0 m/s in a uniform magnetic field B=4.0 T directed into the paper. A capacitor of capacity C=10 μF is connected as shown in figure. Then


A
qA=+80 μC and qB=80 μC
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B
qA=80 μC and qB=+80 μC
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C
qA=0=qB
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D
Charge stored in the capacitor increases exponentially with time
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Solution

The correct option is A qA=+80 μC and qB=80 μC
q=Cε=C(BVl)
=(10×106)(4)(2)(1)
=80 μC=constant
Magnetic force on electron on the coducting rod PQ is towards Q. Therefore A is positively charged and B is negatively charged.

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