A conducting rod PQ of length L=1.0m is moving with a uniform speed V=2.0m/s in a uniform magnetic field B=4.0T directed into the paper. A capacitor of capacity C=10μF is connected as shown in figure. Then
A
qA=+80μC and qB=−80μC
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B
qA=−80μC and qB=+80μC
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C
qA=0=qB
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D
Charge stored in the capacitor increases exponentially with time
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Solution
The correct option is AqA=+80μC and qB=−80μC q=Cε=C(BVl) =(10×10−6)(4)(2)(1) =80μC=constant
Magnetic force on electron on the coducting rod PQ is towards Q. Therefore A is positively charged and B is negatively charged.