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Question

A conducting shell of inner radius R1 and outer radius R2 is given a charge +Q. A point charge q1 is placed inside the shell and q2 is placed outside the shell.


Then for various locations of q1 and q2, match the following entries of columnI with the entries of columnII.

Column-I Column-II
(i). If q1 is at center and q2=0 , then E at center of shell due to charge on outer surface of shell is (a). q14πε0r2
(ii). If q1 is at center and q2 is at distance r from the center, then E at a point distant r2 (>r) from the center of the shell due to outer surface charge is (b). Zero
(iii). If q1 is not at center and q2=0 , then E at point P (P is at distance r from q1 due to charge of the inner surface of shell) is (c). Cant be determined

A
ib , iic , iiia
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B
ib , iib , iiic
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C
ib , iia , iiic
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D
ia , iib , iiic
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Solution

The correct option is A ib , iic , iiia
Let the charge of the outer radius be Q.

Case-I:


Since q2=0, So we can say that the charge Q+q1 on outer surface will be distributed uniformly. Hence, electric field of Q+q1 at center will be zero.

Case -II :

Since, the charge distribution on outer surface is non uniform, it is mathematically impossible to find the electric field intensity at an outside point.

Case -III:


Net field at point P due to q1 and q1 should be zero.
Eq1+Eq1=0
Eq1=Eq1=q14πε0r2 (towards ceter)

Hence, option (a) is the correct alternative.

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