Question

A conductivity cell was filled with 0.1 M NaClsolution at 25 deg C . Its resistance was found to be 176.6 ohm. The conductivity of this solution is 9.2 * 10 ^-3 S cm^-1. The cross sectional area of teh electrodes used was 4 cm^2. What must have been the distance between the electrodes?

Answer 1

Dear student,

As we know that, resistance (R) is related to the distance between the electrode (l) and conductivity (k) by the relation:

$R=\frac{l}{kA}$
Where A is the cross sectional area of the electrode.
Then, $l=RkA=176.6ohm\times 9.2\times {10}^{-3}Sc{m}^{-1}\times 4c{m}^2=6.50cm$

distance between the electrodes = 6.50 cm

Best Wishes !