A conductor is moving with a velocity of $12 m s e c^{- 1}$ perpendicular to the magnetic field of induction $0.45 T$ . An emf of $7.4 V$ is induced in the conductor. Find the length of the conductor.

4.56 m

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3.08 m

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1.37 m

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2.24 m

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Solution

The correct option is C $1.37 m$
Given:
Magnetic field, $B = 0.45 T$ ,
Induced emf, $ϵ$ = 7.4 V and
Velocity, $v = 12 m s e c^{- 1}$
The induced emf, $ϵ$ = $B l v$ , where $l$ is the length of the conductor.
So, $l$ = $\frac{ϵ}{B v}$
$\Rightarrow \frac{7.4}{0.45 \times 12}$ $= 1.37 m$ .

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